while loop stops working after second user input C++ -

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i trying implement feature program says "do want quit?" if 'y or 'y' exit program. if 'n' or 'n' rerun menu , let user whatever want.

the issue facing menu runs first time , user can yes or no. second time can yes or no. third time when reaches while loop infinitely outputs menu.

can please advise?

the code menu 

        char exitinput = null;         char y = 'y', y = 'y', n = 'n', n = 'n';         while (exitinput != y || exitinput != y || exitinput == n || exitinput == n)         {             cout << "*\t please choose 1 of following options. \t *" << endl;              cout << "1. \t" << "transfer amount \n"                  << "2. \t" << "list recent transactions \n"                  << "3. \t" << "display account details , current balance \n"                  << "4. \t" << "quit \n";              int menuselection;             cout << "enter option here: ";             cin >> menuselection;              switch (menuselection)             {             case 1:             .......             case 2:                 cout << "do want exit application? ";                 cin >> exitinput;             }         }

this condition

while (exitinput != y || exitinput != y || exitinput == n || exitinput == n)

will true. have change like:

while (exitinput != y && exitinput != y)

also, initial value of exitinput not make sense, put char exitinput = 'n'


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