mysql - PHP: How to execute try block even if exception found? -

i have try block in exceptions definitely thrown don't want stop execution of try block if happens.

this code:

try {     $querystr = "select * `$current_table` ...";     $query = $db->prepare($querystr);     $query->execute();      while($row = $query->fetch()) {      }  } catch(pdoexception $e) {     //echo $e->getmessage(); } 

this try/catch block inside loop, $current_table changing continously. current table can take 4 values april-june-2014, july-september-2014, october-december-2014 , jan-march-2015. these table names stored in array.

now when query first table , if found, it's , if not found want check other tables , see if exists. if of table not found, throw exception , won't check other tables.

is there way that?

use continue statement:

for (/* condition */) {   try {     // things   } catch (exception $e) {     continue;   }    // won't reach here if exception caught } 

see: http://php.net/continue

example (try out on writecodeonline):

$counter = 0;  ($i = 0; $i < 5; $i++) {   try {     $counter++;     if ($counter != 3) {       throw new exception("test");     }   } catch (exception $e) {     continue;   }    echo "this prints when exception not thrown (when \$counter 3). see: \$counter = " . $counter; }  echo "\n"; var_dump($counter);