xml - Concatenate node values in XSLT -

i need concatenate values of xml based on following:

here xml:

<?xml version="1.0" encoding="utf-8"?> <root>   <parent>     <name>father 1</name>     <child>       <name>f1 - child 1</name>       <age>2</age>     </child>     <child>       <name>f1- child 2</name>       <age>4</age>     </child>   </parent>   <parent>     <name>father 2</name>     <child>       <name>f2 - child 1</name>       <age>2</age>     </child>     <child>       <name>f2 - child 2</name>       <age>4</age>     </child>   </parent> </root> 

and here xslt:

<?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/xsl/transform"     xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl" >   <xsl:output method="xml" indent="yes"/>    <xsl:template match ="root">     <xsl:apply-templates select ="parent/name" />     <xsl:apply-templates select ="parent/child" />    </xsl:template>    <xsl:template match ="parent/name">     <fathername>       <xsl:value-of select ="."/>     </fathername>   </xsl:template>    <xsl:template match ="parent/child">     <childnames>       <xsl:for-each select="name">         <xsl:value-of select="." />         <xsl:if test="position()!=last()">           <xsl:text>, </xsl:text>         </xsl:if>       </xsl:for-each>     </childnames>   </xsl:template>    <xsl:template match="@* | node()">     <xsl:copy>       <xsl:apply-templates select="@* | node()"/>     </xsl:copy>   </xsl:template> </xsl:stylesheet> 

which results this

<?xml version="1.0" encoding="utf-8"?> <fathername>father 1</fathername> <fathername>father 2</fathername> <childnames>f1 - child 1</childnames> <childnames>f1- child 2</childnames> <childnames>f2 - child 1</childnames> <childnames>f2 - child 2</childnames> 

but result need this:

<fathername>father 1</fathername> <childnames>f1 - child 1, f1- child 2</childnames> <fathername>father 2</fathername> <childnames>f2 - child 1, f2 - child 2</childnames> 

can me result need?

essentially, need move line <xsl:apply-templates select ="parent/child" /> out of current template, , template matches parent/name. this:

<xsl:template match="parent/name">   <fathername>     <xsl:value-of select ="."/>   </fathername>   <childnames>       <xsl:apply-templates select ="../child" />   </childnames> </xsl:template> 

the .. here go parent node can select child nodes. note, don't need xsl:for-each in template matching child.

actually, might easier match on parent node parent/name node.

try xslt

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/xsl/transform">   <xsl:output method="xml" indent="yes"/>    <xsl:template match="root">     <xsl:apply-templates select="parent" />   </xsl:template>    <xsl:template match="parent">     <fathername>       <xsl:value-of select ="name"/>     </fathername>     <childnames>        <xsl:apply-templates select ="child" />     </childnames>   </xsl:template>    <xsl:template match="child">       <xsl:if test="position()!=1">         <xsl:text>, </xsl:text>       </xsl:if>       <xsl:value-of select="name" />   </xsl:template>    <xsl:template match="@* | node()">     <xsl:copy>       <xsl:apply-templates select="@* | node()"/>     </xsl:copy>   </xsl:template> </xsl:stylesheet>