how to handle this array in ruby? -

there array this:

    arr = [         {id: 1, status: 3},         {id: 2, status: 5},         {id: 3, status: 5},         {id: 4, status: 5},         {id: 5, status: 5},     ] 

in array, if status of hash 3, change 2, , others change 1. if each hash status not 3, array not change.

i hope output should be:

    arr = [         {id: 1, status: 2},         {id: 2, status: 1},         {id: 3, status: 1},         {id: 4, status: 1},         {id: 5, status: 1},     ] 

if array this:

    arr = [         {id: 1, status: 2},         {id: 2, status: 5},         {id: 3, status: 5},         {id: 4, status: 5},         {id: 5, status: 5},     ] 

each hash status not 3, array doesn't change.

i can make this:

    tmp = false     arr.each |e|         if e[:status].to_i == 3            e[:status] = 2            tmp = true            break         end     end     // note: if tmp == false, array not change     if tmp == true         arr.each |e|             e[:status] = 1  if e[:status].to_i == 5         end     end 

but think bad idea, loop 2 times. has better solution? in advance!

most of answers submitted work correctly if first array element status: 3.

you in single loop, if construct copy of array go, , swap original if found match

arr = [         {id: 1, status: 3},         {id: 2, status: 5},         {id: 3, status: 5},         {id: 4, status: 5},         {id: 5, status: 5}, ];   switch = false new_arr = array(arr.length)  arr.each_with_index |e,i|   if e[:status] == 3     new_elem = { id: e[:id], status: 3 }     switch = true   else     new_elem = { id: e[:id], status: 1 }   end   new_arr[i] = new_elem end  arr = new_arr if switch 

so don't have iterate full array twice, construct unused copy array if there no status: 3.

i think might want consider using different data structure - maybe specific class models state changes you're using. maybe @ of state machine gems.