bash - How to use grep command to print value of a variable in a line? -

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for example,consider below line

<workflowlink condition ="" fromtask ="start" totask ="cmd_start_run"/>

from above line, need print start fromtask ="start" using grep command or using command.

try doing :

$ xmllint --xpath 'string(//workflowlink/@fromtask)' file start  $ xmlstarlet sel -t -v 'string(//workflowlink/@fromtask)' file start  $ saxon-lint --xpath 'string(//workflowlink/@fromtask)' file start

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