xslt - how to refer the value of an xml tag that is passed as value to another xml using xsl -

i have xml goes this:

<root>     <content>         <paragraph>             <image reference="folder-1/folder-2/imagefile.xml"/>         </paragraph>     </content> </root> 

in reference "folder-1/folder-2/imagefile.xml", have path of image file value xml tag.

how access image file , pass path value tag's src attribute?

i tried solution posted in read properties file or text file in xsl, did not work. there other way can done? welcome. in advance.

edited:

the imagefile.xml contains following code:

<container>     <element>         <imagepath>             folder/folder/imagename.jpg         </imagepath>         <altimage>             folder/folder/altimage.jpg         </altimage>     </element> </container> 

when meant solution did not work meant img tag coming in html output has src attribute's value empty this: <img src="" alt=""></img>

the xsl template use this:

<xsl:template match="image">     <img src="{./container/element/imagepath}"/> </xsl:template> 

the image tag expect come this

<img src = "folder/folder/imagename.jpg"/> 

but comes empty. in firefox, see thumbnail broken image, kind of 1 when there no image.

hope helps

  <xsl:template match="/">     <good>       <xsl:variable name="seconddata" select="document(root/content/paragraph/image/@reference)"/>       <img>         <xsl:attribute name="src">           <xsl:value-of select="$seconddata//altimage"/>         </xsl:attribute>       </img>     </good>   </xsl:template> 

only thing important "imagefile.xml" file should within same directory, source or first xml is!! have used .net's own xslcompiledtransform , parser looks within folder source xml comes.